help please

[sky]

write a quadratic formula

the function f has zeros 5 and 1 and f(0)=1.
i don't understand an instruction.
thanks

[ffffff]

vie^'t 1 ca'i function f(x) = a + bx + cx^2 ddi qua ca'c ddie^?m (5,0), (1,0) and (0,1) ?

[sky]

how is that possible ?
its intercepted on x - axis at 5, 1, and 0 ??

[CAptain DaLaZBoi]

the graph will goes up and down... due to its quadratic form.

[Huyenthoai99]

Use this equation: aX^2 + bX + c = F(x) =Y and this equation will pass through these points A(5,0), B(1,0) & C(0,1).
Substitute A, B & C into the equation we will have the following equations:
A(5,0)=> 25a + 5b + c = 0
B(1,0)=> a + b + c = 0
C(0,1)=> c = 1 With 3 equations and 3 unknowns we can solve for a, b, & c...

c= 1, b = -6/5, a = 1/5

Answer: F(x) =( x^2)/5 - 6x/5 + 1

[Huyenthoai99]

From these 2 points x = 5 and x = 1 we could easily see that the Vertex must lie on the line x = 3. This is because we take midpoint between points x=5 and x=1. To find y subs x = 3 into the equation above...

[yeudoi]

Draw a parabola through those 3 points.

The question means that, at y = 0; x = 1 and 5
At x = 0 --> y =1