Need some help with math hw!

[Amavisca]

This is the question:
1,Express y as a funtion of x. The constatnt C is a positive number:

lny = 3 lnx - ln(x+2) + 4lnC Solution y= ?

That is how i did but i cant finish it.

lny = ln(x^3) -lx(x+2) + ln(c^4)

lny = ln [(c^4)*(x^3)]/(x+2)

What is the next step ?? I have no clue, i hope u guys can help some.

2, Find the Range of the following funtion:

f(x)= [ln(2^x) + 1]/(x+5)

Anybody can help me ??? Thnx in advance.

[CAptain DaLaZBoi]

for number 1 ... I believe you can put e to both side so that

e^ln y = e ^ blah blah blah

it will cancel out the ln, and leave u with

y = blah blah blah blah :)

[Amavisca]

Anybody else?? Plz

[Chris-T]

#1) Just as Cap said:

lny = ln {[(c^4)*(x^3)]/(x+2)}

e^(lny) = e^ln {[(c^4)*(x^3)]/(x+2)}

y = (c^4)*(x^3)/(x+2) Note: x /= -2 (x not equal -2)

#2) Range of f(x)= [ln(2^x) + 1]/(x+5)
Bottom of quotient /= zero ==> (x+5) /= 0 ==> x /= -5 and
Range of function ln(something) is (something) > 0, hence
ln(2^x) = x*ln2 ==> always OK ==> x = {Real}
Final: x /= -5 (not equal -5) is the Range

[Amavisca]

Awsome thxn Chris

[Chris-T]

Too bad - I got confused (Domain vs. Range). My previous answer
for #2 was the Domain (not the Range).

Range of x*ln2 is all Real ==> Range of f(x) = {Real}.

Good Lucks

[Amavisca]

ya that is what i think as well :) Again bix thnx